Sm1les 7 vuotta sitten
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      Chapter3/README.md
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      Chapter3/chapter3.md

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Chapter3/README.md

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+# 第2章 线性模型
+主要贡献者:
+- [Sm1les](https://github.com/Sm1les)

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Chapter3/chapter3.md

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+### 3.7
+
+$$ w=\cfrac{\sum_{i=1}^{m}y_i(x_i-\bar{x})}{\sum_{i=1}^{m}x_i^2-\cfrac{1}{m}(\sum_{i=1}^{m}x_i)^2} $$
+
+令式(3.5)等于0:
+$$ 0 = w\sum_{i=1}^{m}x_i^2-\sum_{i=1}^{m}(y_i-b)x_i $$
+$$ w\sum_{i=1}^{m}x_i^2 = \sum_{i=1}^{m}y_ix_i-\sum_{i=1}^{m}bx_i $$
+由于令式(3.6)等于0可得$ b=\cfrac{1}{m}\sum_{i=1}^{m}(y_i-wx_i) $,又$ \cfrac{1}{m}\sum_{i=1}^{m}y_i=\bar{y} $,$ \cfrac{1}{m}\sum_{i=1}^{m}x_i=\bar{x} $,则$ b=\bar{y}-w\bar{x} $,代入上式可得:
+$$ 
+\begin{aligned}	 
+    w\sum_{i=1}^{m}x_i^2 & = \sum_{i=1}^{m}y_ix_i-\sum_{i=1}^{m}(\bar{y}-w\bar{x})x_i \\\\
+    w\sum_{i=1}^{m}x_i^2 & = \sum_{i=1}^{m}y_ix_i-\bar{y}\sum_{i=1}^{m}x_i+w\bar{x}\sum_{i=1}^{m}x_i \\\\
+    w(\sum_{i=1}^{m}x_i^2-\bar{x}\sum_{i=1}^{m}x_i) & = \sum_{i=1}^{m}y_ix_i-\bar{y}\sum_{i=1}^{m}x_i \\\\
+    w & = \cfrac{\sum_{i=1}^{m}y_ix_i-\bar{y}\sum_{i=1}^{m}x_i}{\sum_{i=1}^{m}x_i^2-\bar{x}\sum_{i=1}^{m}x_i}
+\end{aligned}
+$$
+又$ \bar{y}\sum_{i=1}^{m}x_i=\cfrac{1}{m}\sum_{i=1}^{m}y_i\sum_{i=1}^{m}x_i=\bar{x}\sum_{i=1}^{m}y_i $,$ \bar{x}\sum_{i=1}^{m}x_i=\cfrac{1}{m}\sum_{i=1}^{m}x_i\sum_{i=1}^{m}x_i=\cfrac{1}{m}(\sum_{i=1}^{m}x_i)^2 $,代入上式即可得式(3.7):
+$$ w=\cfrac{\sum_{i=1}^{m}y_i(x_i-\bar{x})}{\sum_{i=1}^{m}x_i^2-\cfrac{1}{m}(\sum_{i=1}^{m}x_i)^2} $$
+
+【注】:式(3.7)还可以进一步化简为能用向量表达的形式,将$ \cfrac{1}{m}(\sum_{i=1}^{m}x_i)^2=\bar{x}\sum_{i=1}^{m}x_i $代入分母可得:
+$$ 
+\begin{aligned}	  
+     w & = \cfrac{\sum_{i=1}^{m}y_i(x_i-\bar{x})}{\sum_{i=1}^{m}x_i^2-\bar{x}\sum_{i=1}^{m}x_i} \\\\
+     & = \cfrac{\sum_{i=1}^{m}(y_ix_i-y_i\bar{x})}{\sum_{i=1}^{m}(x_i^2-x_i\bar{x})}
+\end{aligned}
+$$
+又$ \bar{y}\sum_{i=1}^{m}x_i=\bar{x}\sum_{i=1}^{m}y_i=\sum_{i=1}^{m}\bar{y}x_i=\sum_{i=1}^{m}\bar{x}y_i=m\bar{x}\bar{y}=\sum_{i=1}^{m}\bar{x}\bar{y} $,则上式可化为:
+$$ 
+\begin{aligned}
+    w & = \cfrac{\sum_{i=1}^{m}(y_ix_i-y_i\bar{x}-x_i\bar{y}+\bar{x}\bar{y})}{\sum_{i=1}^{m}(x_i^2-x_i\bar{x}-x_i\bar{x}+\bar{x}^2)} \\\\
+    & = \cfrac{\sum_{i=1}^{m}(x_i-\bar{x})(y_i-\bar{y})}{\sum_{i=1}^{m}(x_i-\bar{x})^2} 
+\end{aligned}
+$$
+若令$ \mathbf{X}=(x_1,x_2,...,x_m) $,$ \mathbf{X}_{demean} $为去均值后的$ \mathbf{X} $,$ \mathbf{y}=(y_1,y_2,...,y_m) $,$ \mathbf{y}_{demean} $为去均值后的$ \mathbf{y} $,其中$ \mathbf{X} $、$ \mathbf{X}_{demean} $、$ \mathbf{y} $、$ \mathbf{y}_{demean} $均为m行1列的列向量,代入上式可得:
+$$ w=\cfrac{\mathbf{X}_{demean}\mathbf{y}_{demean}^T}{\mathbf{X}_{demean}\mathbf{X}_{demean}^T}$$