3 İşlemeler f2dcfa678e ... 95f6c3ecd3

Yazar SHA1 Mesaj Tarih
  Sm1les 95f6c3ecd3 update errata 1 yıl önce
  )s b8b2974d98 Update errata.md 1 yıl önce
  )s a5666092a9 修复【6.6.4 式(6.70)的推导】中的错误 1 yıl önce
2 değiştirilmiş dosya ile 4 ekleme ve 3 silme
  1. 3 3
      docs/chapter6/chapter6.md
  2. 1 0
      docs/errata.md

+ 3 - 3
docs/chapter6/chapter6.md

@@ -997,7 +997,7 @@ $$
 $$
 
 
-再将此式代回$\boldsymbol{w}^{\mathrm{T}} \mathbf{S}_{b}^{\phi} \boldsymbol{w}$可得
+再将此式代回$\boldsymbol{w}^{\mathrm{T}} \mathbf{S}_{w}^{\phi} \boldsymbol{w}$可得
 
 
 $$
@@ -1038,12 +1038,12 @@ $$
 $$
 
 
-将上述三项的化简结果代回再将此式代回$\boldsymbol{w}^{\mathrm{T}} \mathbf{S}_{b}^{\phi} \boldsymbol{w}$可得
+将上述三项的化简结果代回再将此式代回$\boldsymbol{w}^{\mathrm{T}} \mathbf{S}_{w}^{\phi} \boldsymbol{w}$可得
 
 
 $$
 \begin{aligned}
-\boldsymbol{w}^{\mathrm{T}} \mathbf{S}_{b}^{\phi} \boldsymbol{w}&=\boldsymbol{\alpha}^{\mathrm{T}} \mathbf{K} \mathbf{K}^{\mathrm{T}} \boldsymbol{\alpha}-m_0\boldsymbol{\alpha}^{\mathrm{T}} \hat{\boldsymbol{\mu}}_{0} \hat{\boldsymbol{\mu}}_{0}^{\mathrm{T}} \boldsymbol{\alpha}-m_1\boldsymbol{\alpha}^{\mathrm{T}} \hat{\boldsymbol{\mu}}_{1} \hat{\boldsymbol{\mu}}_{1}^{\mathrm{T}} \boldsymbol{\alpha}\\
+\boldsymbol{w}^{\mathrm{T}} \mathbf{S}_{w}^{\phi} \boldsymbol{w}&=\boldsymbol{\alpha}^{\mathrm{T}} \mathbf{K} \mathbf{K}^{\mathrm{T}} \boldsymbol{\alpha}-m_0\boldsymbol{\alpha}^{\mathrm{T}} \hat{\boldsymbol{\mu}}_{0} \hat{\boldsymbol{\mu}}_{0}^{\mathrm{T}} \boldsymbol{\alpha}-m_1\boldsymbol{\alpha}^{\mathrm{T}} \hat{\boldsymbol{\mu}}_{1} \hat{\boldsymbol{\mu}}_{1}^{\mathrm{T}} \boldsymbol{\alpha}\\
 &=\boldsymbol{\alpha}^{\mathrm{T}} \cdot\left(\mathbf{K} \mathbf{K}^{\mathrm{T}} -m_0\hat{\boldsymbol{\mu}}_{0} \hat{\boldsymbol{\mu}}_{0}^{\mathrm{T}} -m_1\hat{\boldsymbol{\mu}}_{1} \hat{\boldsymbol{\mu}}_{1}^{\mathrm{T}} \right)\cdot\boldsymbol{\alpha}\\
 &=\boldsymbol{\alpha}^{\mathrm{T}} \cdot\left(\mathbf{K} \mathbf{K}^{\mathrm{T}}-\sum_{i=0}^{1} m_{i} \hat{\boldsymbol{\mu}}_{i} \hat{\boldsymbol{\mu}}_{i}^{\mathrm{T}} \right)\cdot\boldsymbol{\alpha}\\
 &=\boldsymbol{\alpha}^{\mathrm{T}} \mathbf{N}\boldsymbol{\alpha}\\

+ 1 - 0
docs/errata.md

@@ -7,6 +7,7 @@
 - 181页,“式(10.14)的推导”中将式(10.14)化简成式(10.15)目标函数形式时,第⑥步中的$-\boldsymbol{x}_i^{\top}\mathbf{W}^{\top} \mathbf{x}_i$改为$-\boldsymbol{x}_i^{\top} \mathbf{W}\mathbf{W}^{\top} \mathbf{x}_i$(感谢@huishengye)
 - 195页,“式(10.31)的目标函数形式”中的$\operatorname{tr}\left(\mathbf{Z}\mathbf{M}\mathbf{Z}\mathbf{Z}^{\top}\right)$改为$\operatorname{tr}\left(\mathbf{Z}\mathbf{M}\mathbf{Z}^{\top}\right)$(感谢@CoderKingXY)
 - 86页,“样本内积$\boldsymbol{x}_i^{\mathrm{T}\boldsymbol{x}_j}$”改为“样本内积$\boldsymbol{x}_i^{\mathrm{T}}\boldsymbol{x}_j$”(感谢南瓜书读者交流群13的@.)
+- 97页、98页,将其中的“$\boldsymbol{w}^{\mathrm{T}} \mathbf{S}_{b}^{\phi} \boldsymbol{w}$”改为“$\boldsymbol{w}^{\mathrm{T}} \mathbf{S}_{w}^{\phi} \boldsymbol{w}$”(感谢南瓜书读者交流群6的@Sodas)
 
 ## 第2版第5次印刷(2023.11)
 - 98页,“6.6.5 核对率回归”中的第2个公式,其中的$\boldsymbol{x}_{i}$改为$\boldsymbol{z}_{i}$(感谢南瓜书读者交流群11的@[太阳]🌈)